ou81aswell

I have setup a Night Owl NONB-84500 system and it works as advertised. I am using an application called NetViewer to look at the video over my LAN. I can also see the DVR using Internet Explorer (via the dvrocx.ocx ActiveX control) I would like to be able to capture still images from it (every half-hour or so) and dump them to a web server so I can view them from any web browser without the need for an ActiveX control to be installed. I don't think the software bundled with the DVR does this. Questions 1. Are there any other software packages that I can use in conjunction with this system? I'd be interested to see what other types of applications are possible. 2a. I'm a software developer and would like to know if there is a software developers kits that would allow me to create my own applications using the DVR. I'd like to be able to capture camera images and then upload them to a web server as described above. 2b. Is there any support and / or documentation about using the dvrocx.ocx ActiveX control. I played with it and was able to get it running in a simple VB application but was not able to do anything useful with it as it wouldn't compile (I could run it only within the VB environment and not as a stand-alone application). One thing I was able to do inside VB was to mimick the netviewer application (netviewer seems to be a very simple ActiveX container... all of the functionality of it is actually in the dvrocx.ocx control). I used a resizable window (you can't resize the netviewer window) and by simply resizing the dvrocx control from within my app, all of the camera windows were also resized and I could adjust the window from very small to very large. I'd like to be able to compile this code into a stand-alone executable application but VB simply crashes when I try to compile it. It probably needs some sort of license file in order to allow it to be used in a development environment. Thanks for any of your help and suggestions.

Can anyone suggest a forum where questions like this one are likely to be answered? Thanks.