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Thanks to all So I realized, even if I use the same type of compression and the same resolution, the size of each image, will have different values for each type of DVR. In the future if I work with another dvr, I have to use other software to calculate the storage space There are some approximate values that I can use for all dvr knowing the type of compression and resolution?

i'm going use the samsung SHR-2040

i´m going use the samsung-2040, , but i don´t have any calculator.... someone knows, when i can get a storage calculator in the net? Where can I find a calculator storage via Web? or a good image estimator ? i still do not understand how the methods of compression( mpeg4, mjpeg(30) mjpeg(10), etc...) and resolution are related and affect the size of the video

i´m going use the samsung-2040, , but i don´t have any calculator.... someone knows, when i can get a storage calculator in the net? Where can I find a calculator storage via Web? or a good image estimator ? i still do not understand how the methods of compression( mpeg4, mjpeg(30) mjpeg(10), etc...) and resolution are related and affect the size of the video

hi, i am a newbie in the cctv systems. i have some problems in calculating the storage needs in a cctv system. i know that the factors that i have to considered when calculating storage needs are: -number of cameras -number of hours per day, that the camera will be recording -how long the data must be stored - frame rate , compression, image quality and complexity for the bellow exemple (per example) : if i have 1 camera whit: resolution= 640 * 480 frames per second=25 period of storage= 8 hours compression = MJPEG (50) i know that i have to use this formula (FOR 1 CAMERA): required storage space=image size* frames per second * period of request my principal question is how i can calculating the image size? and how resolution and compression influences the image size? and for the case that i use the m4peg? how can i know the storage requeried ? how can i know the bandwidth requeried ? can anybody help me? the only solution is make a pratical test?? best regards

i don´t have the time recording table of the DVR. what you are saying is that is impossible to know the storage needs even if i knew the resolution,frame rate , compression mode(Mpeg4 or mjpeg), number of cameras, etc....unless i do a pratical test. so, when i need install a diferents cameras or DVR´s, whit a diferents resolutaion , i have to do new tests? thanks for your help, i am a newbie in cctv, and all information are welcome.

Ora viva... Eu sou de Matosinhos Viva Portugal

hi..i have some problems in calculating the storage needs in a cctv system. i know that the factors that i have to considered when calculating storage needs are: -number of cameras -number of hours per day, that the camera will be recording -how long the data must be stored - frame rate , compression, image quality and complexity for the bellow exemple : if i have 1 camera whit: resolution= 640 * 480 frames per second=25 period of storage= 8 hours compression = MJPEG (50) i know that i have to use this formula (FOR 1 CAMERA): required storage space=image size* frames per second * period of request my principal question is how i can calculating the image size? how resolution and compression influences the image size? can anybody help me? best regards

Hello to everyone My name is luis and i´m from Portugal and I ´m a beginner in the CCTV systems. I'm here to learn and to help. best regards